Grand Canyon MGT455 week 2 quiz 2

· A certain project activity has an ES (early start) of 10 and a late start (LS) of 14. The total slack for this activity is:

14

9

4

5

· A certain project activity has an EF (early finish) of 11 and a late finish (LF) of 11. The total slack for this activity is:

-8

-12

0

24

· Activity C has two predecessor activities: Activity A and Activity B. The EF (early finish) of Activity A is 5. The EF (early finish) of Activity B is 7. Therefore, the ES (early start) of Activity C is:

5

6

7

8

· A given project’s expected duration along its critical path is 50 days, based on optimistic, most likely, and pessimistic duration estimates. What is the probability that the project will finish on or before 50 days.

0.50

1.00

0.00

0.25

· A given project’s duration along its critical path is 33 days and the total slack for one of the activities is 1 day. The planned finish time for the project is:

31 days

33 days

32 days

34 days

· A given project’s expected duration along its critical path is 32 days. The project’s standard deviation along its critical path is 4 days. What is the probability that the project will finish on or before 35 days.

0.78230

0.27337

0.77935

0.77337

· For the project schedule below, if activity D gets delayed by 1 day, the project end date will get delayed by:

0 days

1 day

2 days

3 days

· For the project schedule below, if activity C gets delayed by 1 day, the project end date will get delayed by:

0 days

1 day

2 days

3 days

· A certain project activity has an EF (early finish) of 11 and a late finish (LF) of 16. The total slack for this activity is:

6

16

-10

5

· A certain project has ten activities. Two activities each have a total slack of 5 days. The total duration of the project’s critical path is 40 days. The duration of the project is ________.

30 days

5 days

40 days

35 days

· A given project’s expected duration along its critical path is 22.5 days. Management eventually wants to know the probability that the project will finish on or before 28 days. The project’s standard deviation along its critical path is 2.03. The approximate computed z value is:

2.71

0.76

4.66

1.00

· Activity F has one predecessor activity: Activity E. The EF (early finish) of Activity E is 18. Therefore, the ES (early start) of Activity F is:

6

24

18

12

· For the project schedule below, the critical path is:

A – C – E

cannot determine

A – B – C – D – E – F

B – D – F

· A certain project activity has an EF (early finish) of 29 and a late finish (LF) of 29. The total slack for this activity is:

0

23

-15

-23

· Activity C has two predecessor activities: Activity A and Activity B. Activity A has finished; however, Activity B has not yet finished. Which statement below is most accurate?

Activity C cannot start, since Activity B has not yet finished.

Activity C can start, since Activity B will eventually finish.

Activity C can start, since Activity A has finished.