IHP 340-Find the expected count and the contribution

Question # 00397460 Posted By: rey_writer Updated on: 09/29/2016 10:54 PM Due on: 09/30/2016
Subject Statistics Topic General Statistics Tutorials:
Question
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1. Chapter 7, Section 2, Exercise 030
Find the expected count and the contribution to the chi-square statistic for the (Group 2, No) cell
in the two-way table below. Round your answer for the excepted count to one decimal place,
and your answer for the contribution to the chi-square statistic to three.
Yes
56
136
68
26

Group 1
Group 2
Group 3
Total
Expected Count=
Contribution to the Chi-square statistic=

No
42
57
24
133

Total
98
203
92
393

2. Chapter 7, Section 2, Exercise 031
Find the expected count and the contribution to the chi-square statistic for the (A, G) cell in the
two-way table below. Round your answer for the excepted count to one decimal place, and your
answer for the contribution to the chi-square statistic to three decimal places.
D
36
76
19
131

E
33
94
35
162

A
B
C
Total
Expected Count:
Contribution to the chi-square statistic:

F
37
68
29
134

G
34
57
30
121

Total
140
295
113
548

3. Chapter 7, Section 2, Exercise 032
Find the expected count and the contribution to the chi-square statistic for the (Treatment,
Agree) cell in the two-way table below. Round your answer for the excepted count to one
decimal place, and your answer for the contribution to the chi-square statistic to three decimal
places.
Strongly Agree

Agree

Control
35
49
Treatment
64
46
Expected count:
Contribution to the chi-square statistic:

Neutral

Disagree

3
11

19
4

Strongly
Disagree
11
0

4. Chapter 7, Section 2, Exercise 033
Find the expected count and the contribution to the chi-square statistic for the (Group 1, Yes)
cell in the two-way table below. Round your answer for the excepted count to one decimal place,
and your answer for the contribution to the chi-square statistic to three decimal places.
Group 1
Group 2
Expected Count:

Yes
737
1163

No
273
324

Contribution to the chi-square statistic:
5. Chapter 8, Section 2, Exercise 034
Consider the data with analysis shown in the following computer output. What is the pooled
standard deviation? What degrees of freedom are used in doing inferences for these means and
differences in means? Round your answer for the pooled standard deviation to two decimal
places.
Level
A
B
C

N
6
5
4

Mean
9.900
16.800
10.800

Source
DF
SS
Groups
2
133.20
Error
12
74.40
Total
14
207.60
The pooled standard deviation is:
Degrees of freedom:

StDev
2.855
2.168
2.387
MS
66.60
6.20

F
10.74

P
0.002

6. Chapter 8, Section 2, Exercise 038
Consider the data with analysis shown in the following computer output:
Level
A
B
C
D

N
5
5
7
7

Mean
87.332
76.167
80.000
69.333

StDev
5.399
6.555
9.230
6.154

Source
DF
SS
MS
F
P
Groups
3
972.33
324.11
6.64
0.003
Error
20
975.66
48.78
Total
23
1947.99
Is there sufficient evidence of a difference in the population means of the four groups?
Yes
No
7. Chapter 8, Section 2, Exercise 039
Consider the data with analysis shown in the following computer output. What is the pooled
standard deviation? What degrees of freedom are used in doing inferences for these means and
differences in means? Round your answer for the pooled standard deviation to two decimal
places.
Level
A
B
C

N
7
5
5

Mean
85.468
76.167
80.000

StDev
4.978
6.555
9.230

D

7

Source
DF
SS
Groups
3
904.94
Error
20
908.04
Total
23
1812.98
The Pooled standard deviation is:
Degree of freedom:

69.333

MS
301.65
45.40

6.154

F
6.64

P
0.003

8. Chapter 9, Section 2, Exercise 028
Use the following ANOVA table for regression to answer the questions. Give the F –statistic and P
–value.
Analysis of Variance
Source
DF
SS
MS
F
P
Regression
1
292.0
292.0
2.31
0.130
Residual Error
174
21993.6
126.4
Total
175
22285.6
The F –statistic is:
The P –value is:
Choose the conclusion of this test using a 5 % significance level.
A. Do not reject Upper H0. We did not find evidence that the model is not effective.
B. Do not reject Upper H0. We did not find evidence that the model is effective.
C. Reject Upper H0. The model is not effective.
D. Reject Upper H0. The model is effective.
9. Chapter 9, Section 2, Exercise 029
Use the following ANOVA table for regression to answer the questions. Give the F –statistic and P
–value. Enter the exact answers.
Analysis Variance
Source
DF
SS
MS
F
P
Regression
1
3396.1
3396.1
20.6
0.000
Residual error
174
28692.6
164.9
Total
175
32088.7
The F –statistic is:
The P –value is:
Choose the conclusion of this test using a 5 % significance level.
A. Do not reject Upper H0. We did not find evidence that the model is effective.
B. Do not reject Upper H0. We did not find evidence that the model is not effective.
C. Reject Upper H0. The model is not effective.
D. Reject Upper H0. The model is effective.

10. Chapter 9, Section 2, Exercise 030
Use the following ANOVA table for regression to answer the questions. Give the F –statistic and P
–value.
Response: Y
Source
DF
Sum Sq
Mean Sq
F-value
Pr(>F)
Regression
1
360.28
360.28
11.52
0.001
Residual error
359
11225.93
31.27
Total
360
11586.21
The F statistic is:
The P –value is:
Choose the conclusion of this test using a 5 % significance level.
A. Reject Upper H0. The model is effective.
B. Do not reject Upper H0. We did not find evidence that the model is effective.
C. Do not reject Upper H0. We did not find evidence that the model is not effective.
D. Reject Upper H0. The model is not effective.
11. Chapter 9, Section 2, Exercise 031
Use the following ANOVA table for regression to answer the questions. Give the F –statistic and P –value.
Source
DF
Regression
1
Residual error 342
Total
343
The F –statistic is:

Sum Sq
9.975
1697.346
1707.321

Mean Sq
9.975
4.963

F-value
2.01

Pr(>F)
0.157

The P –value is:
Choose the conclusion of this test using a 5 % significance level.
A.
B.
C.
D.

Reject Upper H Subscript 0. The model is effective.
Do not reject Upper H Subscript 0. We did not find evidence that the model is not effective.
Do not reject Upper H Subscript 0. We did not find evidence that the model is effective.
Reject Upper H Subscript 0. The model is not effective.

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