If 49 admission records are randomly

Question # 00520475 Posted By: rey_writer Updated on: 05/01/2017 05:17 AM Due on: 05/01/2017
Subject Statistics Topic General Statistics Tutorials:
Question
Dot Image

Questions 13 to 15 refer to the following information: The Length of Stay (LOS) for an acute patient in a metropolitan hospital has a mean (µ ) of 5.5 days and a standard deviation (Ï ) of 2.5 days. It is known that the distribution of LOS is skewed. Assume that the number of admission (ie. LOS) records in the hospital database is very large.


Question 13:If 49 admission records are randomly selected from the hospital database, what is the probability that the average LOS (for the sample of 49) is greater than 6 days?

(a) 0.1793

(b) 0.4207

(c) 0.0808

(d) 0.4192

(e) cannot be determined unless Length of Stay (LOS) is normally distributed


Question 14: If 9 admission records are randomly selected from the hospital database, what is the probability that the average LOS (for the sample of 9) is greater than 6 days?

(a) 0.1793

(b) 0.4207

(c) 0.2743

(d) 0.2257

(e) cannot be determined unless Length of Stay (LOS) is normally distributed


Question 15: If 16 admission records are to be randomly selected from the hospital database, what is the standard error of the LOS sample mean (for the sample of 16)?

(a) 2.5

(b) 0.1563

(c) 1.375

(d) 0.625

(e) cannot be determined as n is too small (n < 30)

Dot Image
Tutorials for this Question
  1. Tutorial # 00517402 Posted By: rey_writer Posted on: 05/01/2017 05:17 AM
    Puchased By: 3
    Tutorial Preview
    The solution of If 49 admission records are randomly...
    Attachments
    1_(2).zip (2091.69 KB)
    Recent Feedback
    Rated By Feedback Comments Rated On
    mit...ins9 Rating Provide the work at reasonable prices 06/09/2017

Great! We have found the solution of this question!

Whatsapp Lisa