How far is the squirrel from its initial position

Solve the all parts of given question:

Question: The position of a squirrel running in a park is given by r = [(0.280m/s)t+(0.0360m/s2)t2]i^+ (0.0190m/s3)t3j^.

Part A: At 5.93s, how far is the squirrel from its initial position?

Part B: At 5.93s, what is the magnitude of the squirrel's velocity?

Part C: At 5.93s, what is the direction (in degrees counterclockwise from +x-axis) of the squirrel's velocity?

Include work and exact answer please! Thank you!