Chemical Reaction Engineering

Question # 00083389 Posted By: solutionshere Updated on: 07/20/2015 05:09 AM Due on: 08/19/2015
Subject General Questions Topic General General Questions Tutorials:
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Problem 3.4 (Octave Levenspiel)

A 10-minute experimental run shows that 75% of liquid reactant is converted to product by a half-order rate. What would be the fraction converted in a half-hour run?

Problem 3.6 (Octave Levenspiel)

After 8 minutes in a batch reactor reactant (CA0 = 1 mol/L) is 80% converted; after 18 minutes, conversion is 90%. Find a rate equation to represent this reaction.

Problem 3.11 & 3.12 (Octave Levenspiel)

Aqueous A at a concentration of CA0 = 1 mol/L is introduced into a batch reactor where it reacts away to form product R according to stoichiometry

Aà R

The concentration of A in the reactor is monitored at various times, as shown below:

Time, min CA, mol/m3

0 1000

100 500

200 333

300 250

400 200

(a) For CA0 = 500 mol/m3 find the conversion of reactant after 5 hours in the batch reactor.

(b) Find the rate expression for the reaction.

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Tutorials for this Question
  1. Tutorial # 00078076 Posted By: solutionshere Posted on: 07/20/2015 05:09 AM
    Puchased By: 3
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    At t=10 min, CA= (1-0.75)*CA0 i.e., CA=0.25*CA0 (...
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