…+ x = xx The total xxxxxx of checkout xxxxx is x x 6 x 4 + x + 2 x 20 xxx xxxxxxxxxx is xxxxxxxxxxxx = 55%2 xxxxxxxxx the mean xx this xxxxxxxxx xxxxxxxxxxxx The xxxx is calculated xxxxxxxxxx xm is xxx midpoint xx xxxx class, xxx fi is xxx corresponding frequency xxxxxxx class x xxxxxxxxx the xxxxxxxx deviation of xxxx frequency distribution xxxxxxxxxxxxx (x)Frequency xxxx x x x x-barf*d*d1 0 x 1 91 xxxxx 5512 xxxxx x - x 92 456-0 xxx 8153 0 x 3 xx xxxx 450 xxx 0…

Preview: will xxx affect xxx median value xxx value that xxx in xxx xxxxxx of xxx data set xxxx not change xxxxx to xxx xxxxxxxxx information xxx Questions 5 xxx 6 Show xxx work xxxx xxx answer, xxxxxxx supporting work, xxxx receive no xxxxxx A xxxxxxx xxx is xxxxxx two times xxx A be xxx event xxxx xxx outcome xx the first xxxx is greater xxxx 4 xxx x be xxx event that xxx outcome of xxxxxx roll xx xx odd xxxxxx 5 What xx the probability xxxx the xxxxxxx xx the xxxxxx roll is xx odd number, xxxxx that xxx xxxxx roll xx greater than xx (10 pts)Event x is xxxxxxxx xxxx is xxxxxxx than 4” xxxxx B is xxxxxxxxx roll xx xx odd xxxxxxxxx To determine xxx and B), xxxxxxxx that xxxxx xxx only x ways to xxxx a value xxxxxxx than xx xxx then xxxxx are 3 xxxx to roll xx odd xxxxxx xxx total xxxxxx of ways xxxx you can xxxx a xxxxx xxxxxxx than x followed by xx odd number xx 2*3 x x Since xxxxx are 36 xxxxxxxx combinations of xxxxxx for xxx xxx rolls, xxx probability of xxxxxxx a value xxxxxxx than x xxxxxxxx by xx odd number xx 6/36, or xxx 6 xxx x and x independent? Why xx why not? xx pts)If x xxx B xxx independent, then xxx and B) x P(A)P(B) xxxx xx above, xxx and B) x 1/6, and xxxx = xxx xxxxx Since xxx and B) x P(A)P(B), the xxx events xxx xxxxxxxxxxx Refer xx the following xxxx to answer xxxxxxxxx 7 xxx x Show xxx work Just xxx answer, withoutsupporting xxxxx will xxxxxxx xx credit x random sample xx STAT200 weekly xxxxx times xx xxxxx is xx follows: 4 xx 15 17 xxx Find xxx xxxxxxxx deviation xxx pts) 8 xxx any of xxxxx study xxxxx xxxxxxxxxx unusual xx the sense xx our textbook? xxxxxxx ?Does xxxx xxxxxx with xxxx intuition? Explain xx pts) The xxxxx of xxxxxx xxxxxx two xxxxxxxx deviations of xxx mean is:14 xx 2*(6 xxxxx x (1 xxxx 26 083)Since xxx of the xxxxxx are xx xxxx interval, xxxxx are no xxxxxx that would xx considered xxxxxxx xx inspection, xxxx of the xxxxxx appear to xx unusual, xx xxxx result xxxx notdiffer from xx intuition Refer xx the xxxxxxxxx xxxxx for xxxxxxxxx 9, 10, xxx 11 Show xxx work xxxx.....