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# What is the point estimate of the true proportion of people who wear hearing aids

Question # 00005521
Subject: Mathematics
Due on: 12/17/2013
Posted On: 12/16/2013 10:51 PM

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1. What is the point estimate of the true proportion of people who wear hearing aids if, in a random sample of 676 people, 35 people had hearing aids? (Points : 6)
0.050
0.052
0.948
0.049

Question 2. 2. The following confidence interval is obtained for a population proportion, p:(0.499, 0.525). What is the point estimate, pq5_7? (Points : 6)
0.525
0.499
0.518
0.512

Question 3. 3. The following confidence interval is obtained for a population proportion, p:0.332 < p < 0.372. What is the margin of error, E? (Points : 6)
0.040
0.352
0.020
0.021

Question 4. 4. What is the critical value e3_1 that corresponds to a level of confidence of 98%? (Points : 6)
2.575
1.75
2.05
2.33

Question 5. 5. What is the margin of error for the 95% confidence interval used to estimate the population proportion, given that n = 184 and x = 93? (Points : 6)
0.0722
0.0650
0.00266
0.126

Question 6. 6. In a clinical test with 2219 subjects, 70% showed improvement from the treatment.
What is the margin of error for the 95% confidence interval used to estimate the population proportion? (Points : 6)
0.0191
0.0254
0.0211
0.0160

Question 7. 7. In a survey of 3000 T.V. viewers, 40% said they watch network news programs. What is the margin of error for the 95% confidence interval used to estimate the population proportion? (Points : 6)
0.0131
0.0201
0.0230
0.0175

Question 8. 8. What is the minimum sample size you should use to assure that your estimate of pq5_7 will be within the required margin of error around the population p? Margin of error: 0.018; confidence level: 99%; and e3_18 are unknown. (Points : 6)
36
72
1
5117

Question 9. 9. What is the minimum sample size you should use to assure that your estimate of pq5_7 will be within the required margin of error around the population p? Margin of error: 0.04; confidence level: 95%; from a prior study, pq5_7 is estimated by the decimal equivalent of 94%. (Points : 6)
136
120
5
408

Question 10. 10. Use the confidence level and sample data to find the margin of error E.

Replacement times for washing machines: 90% confidence; n = 33, e3_29 = 11.2 years,

sigma ? = 2.3 years. (Points : 7)
0.7 years
0.1 years
5.7 years
0.5 years

Question 11. 11. A random sample of 107 light bulbs had a mean life of e3_29 = 590 hours with a standard deviation of sigma ? = 27 hours. Construct a 90 percent confidence interval for the mean life, ?, of all light bulbs of this type.

583 < ? < 597
585 < ? < 595
584 < ? < 596
586 < ? < 594

(Points : 7)

Question 12. 12. Do one of the following, as appropriate: Find the critical value e3_1, find the critical value pq5_3, or state that neither the normal nor the t distribution applies. 91% level of confidence; n = 45; sigma ? is known; population appears to be very skewed.

e3_1 = 1.75
e3_1 = 1.70
pq5_3 = 1.34
pq5_3 = 1.645

(Points : 7)
Neither the normal nor the t distribution applies

Question 13. 13. A random sample of 90 full-grown lobsters had a mean weight of 18 ounces and a standard deviation of s=2.8 ounces. Construct a 98 percent confidence interval for the population mean ?.

17 < ? < 19
18 < ? < 20
17 < ? < 20
16 < ? < 18

(Points : 6)

Question 14. 14. Find the margin of error given 95% confidence interval; n = 91 ; e3_29 = 26, s = 12.3. (Points : 6)
5.27
2.71
3.01
2.56

Question 15. 15. Use the given level of confidence and sample data to construct a confidence interval for the

population mean ?. Assume that the population has a normal distribution. n = 10, e3_29 = 8.0, s = 2.5, 95 percent.

6.24 < ? < 9.76
6.21 < ? < 9.79
6.17 < ? < 9.93
6.55 < ? < 9.45

(Points : 6)

Question 16. 16. Use the margin of error, confidence level, and standard deviation ? to find the minimum sample size required to estimate an unknown population mean ?. Margin of error: \$125, confidence level: 95%, sigma ? = \$524. (Points : 7)
2
68
5
59

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#### Multiple choice Statistics Solutions

Tutorial # 00005326
Posted On: 12/16/2013 10:52 PM
Posted By:
expertden
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Tutorial Preview …(Points x 6)0 xxxxx 02540 02110 xxxxxxxxxxxx 7 7 xx a xxxxxx xx 3000 x V viewers, xxx said they xxxxx network xxxx xxxxxxxx What xx the margin xx error for xxx 95% xxxxxxxxxx xxxxxxxx used xx estimate the xxxxxxxxxx proportion? (Points x 6)0 xxxxx xxxxx 02300 xxxxxxxxxxxx 8 8 xxxx is the xxxxxxx sample xxxx xxx should xxx to assure xxxx your estimate xx pq5_7 xxxx xx within xxx required margin xx error around xxx population xx xxxxxx of xxxxxx 0 018; xxxxxxxxxx level: 99%; xxx e3_18 xxx xxxxxxx (Points x 6)367215117Question 9 x What is xxx minimum xxxxxx xxxx you xxxxxx use to xxxxxx that your xxxxxxxx of xxxxx xxxx be xxxxxx the required xxxxxx of error xxxxxx the xxxxxxxxxx xx Margin xx error: 0 xxx confidence level: xxxx from x xxxxx study, xxxxx is estimated xx the decimal xxxxxxxxxx of xxx xxxxxxx : xxxxxxxxxxxxxxxxxxxx 10 10 xxx the confidence xxxxx and xxxxxx xxxx to xxxx…
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Preview: (Points x 6)0 xxxxx 02540 02110 xxxxxxxxxxxx 7 7 xx a xxxxxx xx 3000 x V viewers, xxx said they xxxxx network xxxx xxxxxxxx What xx the margin xx error for xxx 95% xxxxxxxxxx xxxxxxxx used xx estimate the xxxxxxxxxx proportion? (Points x 6)0 xxxxx xxxxx 02300 xxxxxxxxxxxx 8 8 xxxx is the xxxxxxx sample xxxx xxx should xxx to assure xxxx your estimate xx pq5_7 xxxx xx within xxx required margin xx error around xxx population xx xxxxxx of xxxxxx 0 018; xxxxxxxxxx level: 99%; xxx e3_18 xxx xxxxxxx (Points x 6)367215117Question 9 x What is xxx minimum xxxxxx xxxx you xxxxxx use to xxxxxx that your xxxxxxxx of xxxxx xxxx be xxxxxx the required xxxxxx of error xxxxxx the xxxxxxxxxx xx Margin xx error: 0 xxx confidence level: xxxx from x xxxxx study, xxxxx is estimated xx the decimal xxxxxxxxxx of xxx xxxxxxx : xxxxxxxxxxxxxxxxxxxx 10 10 xxx the confidence xxxxx and xxxxxx xxxx to xxxx.....
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