if det(A)=0 , then AB is singular
Question # 00183206
Posted By:
Updated on: 01/31/2016 03:57 AM Due on: 01/31/2016
Prove the following:
1- if det(A)=0 , then AB is singular .
2- if A and B are invertible then AB is invertible . with (AB)^-1 = B^-1 A^-1
3- if A is invertible and B , C are inverses of A , the B=C .
4- if A is invertible then det (A^-1)= 1/det (A) .
-
Rating:
/5
Solution: if det(A)=0 , then AB is singular